4x^2=4-7x

Solution for 4x^2=4-7x equation:

4x^2=4-7x

We move all terms to the left:

4x^2-(4-7x)=0

We add all the numbers together, and all the variables

4x^2-(-7x+4)=0

We get rid of parentheses

4x^2+7x-4=0

a = 4; b = 7; c = -4;
Δ = b2-4ac
Δ = 72-4·4·(-4)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{113}}{2*4}=\frac{-7-\sqrt{113}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{113}}{2*4}=\frac{-7+\sqrt{113}}{8}
$